5x^2+x-1980=0

Solution for 5x^2+x-1980=0 equation:

5x^2+x-1980=0

a = 5; b = 1; c = -1980;
Δ = b2-4ac
Δ = 12-4·5·(-1980)
Δ = 39601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39601}=199$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-199}{2*5}=\frac{-200}{10}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+199}{2*5}=\frac{198}{10}
=19+4/5
$